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exis [7]
3 years ago
10

Applications of systems of equations

Mathematics
1 answer:
ycow [4]3 years ago
4 0
If m= mc questions and t= t/f questionst=125-m, 8(125-m)+14m=1300, 1000-8m+14m=1300 ,
\left \{ {{t+m=125} \atop {8t+14m=1300}} \right. ,
6m=300 ,
m=50 , t=75
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There were 165 donors last year. Find the number of donors this year using each of the expressions. Do you get the same number w
pochemuha

Answer:

We need to see the expressions given

Step-by-step explanation:

4 0
4 years ago
Graph the following exponential functions and determine the y-intercept, domain, range, and
Ne4ueva [31]

The graph of the exponential function f(x) = 5(2)ˣ is as shown in the attached file.

<h3>How to draw the graph of an exponential Function?</h3>

We want to draw the graph of the exponential function;

f(x) = 5(2)ˣ

At input of x = 0, we have;

f(x) = 5(2)⁰ = 5

At input of x = 1, we have;

f(x) = 5(2)¹ = 10

At x = -1, we have;

f(x) = 5(2)⁻¹ = 2.5

At x = -2, we have;

f(x) = 5(2)⁻² = 1.25

Read more about Graph of Exponential Function at; brainly.com/question/12940982

#SPJ1

8 0
2 years ago
Karen went to the farmers market
Zinaida [17]

Answer:

6 papayas and 11 pineapples

Step-by-step explanation:

So, we need to find an answer of how many papayas and pineapples she bought, and we only spent $48.

So,  papayas are $2.50 each, and Pineapples are $3.00 each and we only bought 17 fruits total.

lets try 8 papayas, and 9 Pineapples.

$2.50 x 8 = $20.00 total on Papayas

$3.00 x 9 = $27.00 total on Pineapples.

That would only be $47 spent total.

Lets try 10 papayas and 7 pineapples.

$2.50 x 10 = $25.00

$3.00 x 7 = $21.00

That would only be a total of $26 spent.

Lets try 6 papayas and 11 pineapples.

$2.50 x 6 = $15.00

$3.00 x 11 = $33.00

This would be a total of $48 spent.

8 0
3 years ago
On for the hyperbola with write an equation for the hyperbola given characteristics.
galina1969 [7]

Answer:

Step-by-step explanation:

3 0
3 years ago
What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10
SashulF [63]
To solve we need to use Pythagoras theorem ( a^{2} +  b^{2} =  c^{2} )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = x^{2}
100+441= x^{2}
\sqrt{541} =  \sqrt{ x^{2} }
23.3≈x

Shorter leg:
10^2 + x^2=21^2
x^2= 21^2-10^2
x^{2}= 441-100 
\sqrt{ x^{2} } = \sqrt{341}
x≈18.47
8 0
3 years ago
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