6*(-5)-3 = -33
6*(-3/2)-3 = -12
6*(7/2)-3 = 18
6*(1)-3=3
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,

Hence, this is the required solution.
Step-by-step explanation:
A
Answer:
12%
Step-by-step explanation:
Answer should be 3 I’m pretty sure