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Travka [436]
3 years ago
13

What number is 15% of 215

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0
15/100 × 215 = 3225/100
= 32.25

i am a mathematics teacher. if anything to ask please pm me
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Who can help me needed for tomorrow please
blagie [28]

a) 170.00 =8n -30

200= 8n

n = 200/8 = 25 items


b) since the expenses increased the profits would decrease

profit = 8(25)-40 = 200-40 = 160

170-160 = 10.00

 profit decreased by $10.00

6 0
3 years ago
Read 2 more answers
Please help me answer these 2 questions, worth lots of points
alexgriva [62]
For the first one, to find x, you are going to take that entire side which would equal to 180 and solve. 2x+20+55=180 would then go down to 2x+65=180 once you add the 20 and 55. Then subtract 65 to both sides and divide your final answer 115/2 which is x=57.5. For the second one it’s 4x-2+21=180, then you will subtract 2 from 21 and get 19. After you would subtract 19 by 180 and divide 4 by each side, getting x=40.25 as your final answer.
7 0
3 years ago
What is the value of x+2y if -3x-6y=24
almond37 [142]

Answer:

- 8

Step-by-step explanation:

Given

3x - 6y = 24 ( divide all terms by - 3 )

x + 2y = - 8

8 0
3 years ago
George earn 3 dollars each time he sweeps and mops in the family room for you trying to earn $17 for tickets to the end of the s
uranmaximum [27]
17+4=21 
21 divided by 3= 7
17 dollars for tickets 
21-4=17
so your answer is 21 he has to sweep the floor 21 times to get tickets

5 0
3 years ago
The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter
VMariaS [17]

Answer:

He must survey 123 adults.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Assume that a recent survey suggests that about 87​% of adults have heard of the brand.

This means that \pi = 0.87

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How many adults must he survey in order to be 90​% confident that his estimate is within five percentage points of the true population​ percentage?

This is n for which M = 0.05. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.05 = 1.645\sqrt{\frac{0.87*0.13}{n}}

0.05\sqrt{n} = 1.645\sqrt{0.87*0.13}

\sqrt{n} = \frac{1.645\sqrt{0.87*0.13}}{0.05}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.87*0.13}}{0.05})^2

n = 122.4

Rounding up:

He must survey 123 adults.

6 0
3 years ago
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