Answer: who knows what the answers is bruh
Step-by-step explanation:
Answer:
The mass of the object is 2.6 grams
Step-by-step explanation:
The density of an object is the ratio between its mass and its volume
The equation of the is d = 
, where
Let us use this equation to solve the question
∵ An object has a density of 1.3 g/cm³
∴ d = 1.3 g/cm³
∵ Its volume is 2 cm³
∴ V = 2 cm³
→ Substitute them in the equation of the denisty above
∵ 1.3 = 
→ Multiply both sides by 2
∴ 2 × 1.3 = 2 ×
∴ 2.6 = m
∴ The mass of the object is 2.6 grams
Answer:
45 ft
Step-by-step explanation:
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Let's first write the equation given
x²+6x-13=0
They have told us to use "Completing the square" method.
So we need write x²+6x-13 as a whole square.
x²+6x-13=0
x²+(2*3*x)-9-4 = 0
x²+(2*3*x)-3²=4
Now we can write the LHS as:
(x - 3)²=2²
Hence,
x-3 can either be 2 or -2
Now,
x - 3=2
x=5
Or,
x - 3=-2
x=1
Therefore now we know that x can either be 1 or 5. So the correct answer is Option B.
