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Fynjy0 [20]
3 years ago
6

Charlie buys a $23,000 mustang in 2006

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

ANd?

Step-by-step explanation:

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Can someone help me please!
Alex777 [14]

Answer:

4x^2+17x+15

Step-by-step explanation:

(4x-3)(x+5)

= 4x(x+5) -3(x+5)

= 4x^2+ 20x -3x + 15

= 4x^2 + 17x + 15

7 0
3 years ago
Please hurry i don't have much time left!
quester [9]

Answer:

Check below

Step-by-step explanation:

That's too bad you haven't attached a rectangle.

Here's an example, with the data you've typed in.

1) When we dilate a rectangle we either grows it or shrink it through a scale factor.

Check the first picture below.

The New Dilated Rectangle A'B'C'D' will follow its coordinates, when the <u>Center of Dilation is at its origin(Middle):</u>

D_{A'B'C'D'}=\frac{1}{2}(x,y)

2) But In this question, <u>B is the center of Dilation</u>. So, Since B is the Dilation Point B=B' .  And More importantly:

\bar{AB}=\frac{1}{2}\bar{A'B'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\\bar{AC}=\frac{1}{2}\bar{A'C'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\

3) So check the pictures below for a better understanding.

6 0
3 years ago
Read 2 more answers
What is the vertex of the absolute value function defined by ƒ(x) = |x + 5| + 7?
Temka [501]
To answer this, you need to know the general form of an absolute value function. the equation for this is f(x<span>) = </span>a|x<span> - </span>h<span>| + </span>k, and in this equation, the vertex is (h, k).

with that information, you can see that your vertex will be (-5, 7). you must take the negative for 5 because the general equation states that your h value is usually subtracted from x. to check your vertex, try plugging it into your general equation:
f(x) = a|x - (-5)| + 7
f(x) = a|x + 5| + 7 ... you see that this matches your given equation. this last part here was just to show why your 5 must be negative; your answer is bolded.
7 0
3 years ago
For 0 ≤ ϴ &lt; 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
2 years ago
Which pair shows equivalent expressions?
Yuliya22 [10]
C is the answer to this question.
4 0
2 years ago
Read 2 more answers
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