Charlie buys a $23,000 mustang in 2006

Can someone help me please!

Alex777 [14]

Answer:

4x^2+17x+15

Step-by-step explanation:

(4x-3)(x+5)

= 4x(x+5) -3(x+5)

= 4x^2+ 20x -3x + 15

= 4x^2 + 17x + 15

7 0

3 years ago

Please hurry i don't have much time left!

quester [9]

Answer:

Check below

Step-by-step explanation:

That's too bad you haven't attached a rectangle.

Here's an example, with the data you've typed in.

1) When we dilate a rectangle we either grows it or shrink it through a scale factor.

Check the first picture below.

The New Dilated Rectangle A'B'C'D' will follow its coordinates, when the Center of Dilation is at its origin(Middle):

$D_{A'B'C'D'}=\frac{1}{2}(x,y)$

2) But In this question, B is the center of Dilation. So, Since B is the Dilation Point B=B' . And More importantly:

$\bar{AB}=\frac{1}{2}\bar{A'B'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\\bar{AC}=\frac{1}{2}\bar{A'C'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\$

3) So check the pictures below for a better understanding.

6 0

3 years ago

Read 2 more answers

What is the vertex of the absolute value function defined by ƒ(x) = |x + 5| + 7?

Temka [501]

To answer this, you need to know the general form of an absolute value function. the equation for this is f(x) = a|x - h| + k, and in this equation, the vertex is (h, k).

with that information, you can see that your vertex will be (-5, 7). you must take the negative for 5 because the general equation states that your h value is usually subtracted from x. to check your vertex, try plugging it into your general equation:
f(x) = a|x - (-5)| + 7
f(x) = a|x + 5| + 7 ... you see that this matches your given equation. this last part here was just to show why your 5 must be negative; your answer is bolded.

7 0

3 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

or

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: