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3 years ago

Which side is adjacent to

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

Answer is on the pic

Step-by-step explanation:

I hope it's helpful!

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Ms. Federman graded 5 papers in 40 minutes. At this rate, how many minutes will it take her to grade 30 papers?

Ksivusya [100]

Answer:

240 minutes

Step-by-step explanation:

If it's 40 minutes for just 5 papers, we need to figure how many minutes it would take to grade just 1. So you have to divide 40 by 5 which is 8. Then 8 time 30 which is 240.

4 0

3 years ago

Pip and Sara win some money and share it in ratio 5:4 pip gets £50 how much did they get all together

N76 [4]

Answer: £90

Step-by-step explanation:

Pip and Sara get some money. They share it in the ratio 5 : 4.

Pip gets £50 so what did Sara get:

Use direct proportion:

5 : 4

50 : x

5x = 200

x = 200/5

x = £40

Pip got £50 and Sara got £40.

Together they got:

= 50 + 40

= £90

4 0

3 years ago

36 (6 - 4x) – 27x = 10x - 31

Colt1911 [192]

The answer is highlighted and I put the work for checking the answer at the bottom

4 0

3 years ago

Simplify

Lapatulllka [165]

Answer:

$\frac{4\sqrt{5} }{5}$

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate.

7 0

3 years ago

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago