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3 years ago

7

Which side is adjacent to

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

Answer is on the pic

Step-by-step explanation:

I hope it's helpful!

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Estimate <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B80%7D%20" id="TexFormula1" title=" \sqrt{80} " alt=" \sqrt{80} " ali

Tamiku [17]

Answer:

8.9

Step-by-step explanation:

Convert √ 80 to a decimal.

8.9442719

Find the number in the tenth place 9 and look one place to the right for the rounding digit 4 . Round up if this number is greater than or equal to 5 and round down if it is less than 5 .

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4 years ago

Norma-Jean [14]

Answer:

36

Step-by-step explanation:

someone told me. this will make it easier for u

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3 years ago

Jason watched a caterpillar move 16 feet in 8 minutes. Jason says that the caterpillar's unit rate is 0.5 foot per minute. Is Ja

MrRa [10]

Answer:

Jason is incorrect.

The caterpillar's rate is 2 ft/min

Step-by-step explanation:

The rate of motion is defined as the quotient between the distance covered (in our case 16 feet) divided by the time it took to cover that distance (in our case 8 minutes)

Then, the rate is:

$rate=\frac{distance}{time} = \frac{16\,\,ft}{8\,\,min} = 2\,\frac{ft}{min}$

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3 years ago

lavan buys a house with a down payment of 12,000. The down payment is 10% of the price of the house house. How much will her mor

Tcecarenko [31]

Her mortgage will be 1,200.

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3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

3 years ago