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lidiya [134]
3 years ago
6

I need some help please As soon as Possible ​

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

9. 32 (1/20) = 1.6

    25 (1.6 = 40

    5x + 5 = 40

     5x + 5 - 5 = 40 - 5

     5x = 35

      (1/5) 5x = 35 (1/5)

       x = 7

10. 24 (1/6) = 4

     4 (4) = 16

      x + 6 = 16

      x + 6 - 6 = 16 - 6

      x = 10

11. 20 (3/4) = 15

    12 (3/4) = 9

     2x - 11 = 9

     2x - 11 + 11 = 9 + 11

     2x = 20

     (1/2) 2x = 20 (1/2)

      x = 10

12. 8 (1/4) = 2

     10 (1/2) = 5

     -3 + x = 5

     -3 + 3 + x = 5 + 3

     x = 8

13. 10 (1/5) = 2

     6 (2) = 12

     2x - 10 = 12

     2x - 10 + 10 = 12 + 10

     2x = 22

     (1/2) 2x = 22 (1/2)

     x = 11

14. 16 (1/8) = 2

     8 (1/2) = 4

     2x - 16 = 4

     2x - 16 + 16 = 4 + 16

     2x = 20

     (1/2) 2x = 20 (1/2)

     x = 10

     

     

       

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Vector question. Let v=<-2,1> u=<3,-5> , find:
lyudmila [28]

Answer:

1. )\vec {v}.\vec{u}= -11

2.) The angle between v and u is 147.52°.

Step-by-step explanation:

Given:

\vec {v}= ( -2 , 1 )\\\vec {u}= ( 3 , -5 )

To Find:

1. \vec {v}.\vec{u}= ?

2.\theta = ?

Solution:

\vec {v}.\vec{u} is scalar product given as,

\vec {v}.\vec{u}=|\vec {v}||\vec {u}|\cos \theta

|\vec {v}|=|(-2, 1)|=\sqrt{(-2)^{2} +1^{2}}=\sqrt{5}\\|\vec {u}|=|(3, 5)|=\sqrt{(3)^{2} +(-5)^{2}}=\sqrt{34}

\vec {v}.\vec{u}=(-2i +j).(3i-5j)\\

Here only i.i = j.j =1 and i.j = j.i = 0

∴ \vec {v}.\vec{u}=(-2\times 3 +1\times -5)\\\vec {v}.\vec{u}=-6-5=-11 \\

Now, Substituting the above values we get

-11=\sqrt{5}\times \sqrt{34}\cos \theta\\ \cos \theta=\frac{-11}{\sqrt{170}} \\ \cos \theta =-0.84366\\\therefore \theta =cos^{-1}(-0.84366)\\\therefore \theta =147.52\°

As it is negative mean \theta is in Second Quadrant Because Cosine is negative in Second Quadrant.

1. )\vec {v}.\vec{u}= -11

2.) The angle between v and u is 147.52°.

5 0
3 years ago
A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
Novay_Z [31]

Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

7 0
4 years ago
Dan used 942 units of electricity from July to October.
Maksim231197 [3]

Answer:

89n

Step-by-step explanation:)

7 0
3 years ago
Read 2 more answers
Casey has a small business making dessert baskets. She estimates that her fixed weekly costs for rent and electricity are $200.
lisov135 [29]

Answer:

a) Total weekly cost = $300

b) For Cassey to break even she has to sell 4 baskets

Step-by-step explanation:

Cost of electricity and rent in a week = $200

Cost of ingredients to make one dessert basket = $2.50

Total cost of making 40 dessert basket= 40*25

= $100

a) Cassey total cost in a week is $200 + $100

= $300

b) if each basket is sold at $25,the total selling price of 40 baskets will be $(25*40)

= $1000.

For Cassey to break even with the cost of production she has to sell y basket.

y = cost of producing 25 baskets / cost of selling 1 basket

y = 100/25

y = 4 baskets

5 0
3 years ago
5) –3x – 3y=3<br> -5x + 2 y = 19
larisa86 [58]

Answer:

x=31

Step-by-step explanation:

-3x-3(19)=3-5x+2

2x-57=5

2x=62

x=31

4 0
3 years ago
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