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Rus_ich [418]
3 years ago
13

The equation of line CD is y=3x-3. Write an equation of a line perpendicular to line CD in slop-intercept form that contains poi

nt (3,1)
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0
Y = -x/3 + b1 = -3/3 + b              
 substitute values of point1 = -1 + b                  
then reduce2 = b                          
 add one to both sides y = -x/3 + 2
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Marat540 [252]
What you should know for this case is that all quadratic functions represent a parabola.
 We have then that the function with vertice (-2, 0) is:
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 Answer:
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 (option 3)
4 0
4 years ago
Find cos b in the triangle
monitta

Answer:

okay I need help please

Step-by-step explanation:

find cos b in the triangle

7 0
3 years ago
Determine: t(4) for t (x)=2x²-3/5
QveST [7]
The answer is 31.4. I hope this helps.
7 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Alexxandr [17]

Use 2 points on the line to find the slope.

Slope = change in y / change in x

The two points used: (-2,5) and ( 1,-10)


slope = (-10 -5) /(1- -2) = -15/3 = -5


the y intercept is where the line is at in the y direction when it crosses the x axis at 0.


the y intercept is -5


The equation is y = -5x -5

5 0
2 years ago
Read 2 more answers
I’m stuck please help
andrew-mc [135]
You divide 3 on both sides then you equation is the square root of -4x-4 =4 and you square the number on both sides because u need to do the same things on both sides and you get -4x-4=16 subtract by 4 on boyh sides to get -4x=20 and divide by -4 on both aises to get x=-5

I hope this helped i know this explanation is a bit wonky

7 0
3 years ago
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