Answer: (a) The angle the ramp forms with the driveway, s° = 4.004° (3 d.p)
(b) The driveway has to be, s = 28.57 ft
(c) The ramp will be 28.64 ft long
Step-by-step explanation:
First key thing to know is that the %grade of a ramp = rise/ramp run
%grade of a ramp = 7% = 0.07
(Kindly find attached a diagram to assist with understanding).
Also note that, <em>the ramp run is not the same as the ramp length</em>
(a) the angle, θ, is the angle of slope between the driveway and the ramp,
tan θ = 0.07,
θ = tan⁻¹ 0.07 = 4.004° (3 d.p)
(b) the length of the driveway (s) is the same as the length of the ramp run, so, %grade of a ramp = rise/ramp run
0.07 = 2/s
s = 2/0.07 = 28.57 ft (2 d.p)
(c) the length of the ramp can be found by using Pythagoras' theorem,
L = ramp length =![\sqrt{rise^{2} + ramprun^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7Brise%5E%7B2%7D%20%2B%20ramprun%5E%7B2%7D%20%7D)
L = ![\sqrt{2^{2} +28.571^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B2%5E%7B2%7D%20%2B28.571%5E%7B2%7D%20%7D)
L = ![\sqrt{820.3041}](https://tex.z-dn.net/?f=%5Csqrt%7B820.3041%7D)
L = 28.64 ft (2 d.p)