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rjkz [21]
3 years ago
9

A shoebox is covered with packing paper before being shipped. The paper cost $0.02 per square inch. How much will it cost to cov

er three pairs of shoes?
Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

Cost of packing 3 boxes = 3*(2LW + 2WH + 2LH) * 0.02 dollars

Step-by-step explanation:

Assume length of box = L in

height of box = H in

width of box = W in

surface area = (2LW + 2WH + 2LH) sq. in.

surface area of 3 boxes = 3*(2LW + 2WH + 2LH) sq.in.

Cost of packng one sq. in.= 0.02 dollars

Cost of packing 3 boxes = 3*(2LW + 2WH + 2LH) * 0.02 dollars

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AysviL [449]

You can take x = a, 2y = b and then can apply the binomial theorem.

The expansion of given expression is given by:

Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is

<h3>What is binomial theorem?</h3>

It provides algebraic expansion of exponentiated(integer) binomial.

According to binomial theorem,

(a+b)^n = \sum_{i=0}^n ^nC_i a^ib^{n-i}

<h3>How to use binomial theorem for given expression?</h3>

Taking a = x, and b =2y, we have n = 7, thus:

(x+2y)^7 = \: ^7C_0x^0(2y)^7 + \: ^7C_1x^1(2y)^6 + \: ^7C_2x^2(2y)^5 + \: ^7C_3x^3(2y)^4 + \:^7C_4x^4(2y)^3 + \:^7C_5x^5(2y)^2 + \:^7C_6x^6y^1 + \: ^7C_0x^7y^0\\\\&#10;(x+2y)^7 = 128y^7 + 448xy^6 + 672x^2y^5 + 560x^3y^4 + 280x^4y^3 + 84x^5y^2 + 14x^6y + x^7\\\\&#10;(x+2y)^7 = x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7

Thus, Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is correct.

Learn more about binomial theorem here:

brainly.com/question/86555

6 0
3 years ago
Answer the question 5+5+5+5+5
JulsSmile [24]

Answer:

25

Step-by-step explanation:

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3 years ago
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Flauer [41]

1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

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Answer:

area = 144\pi

Step-by-step explanation:

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horrorfan [7]
I think it represents the height hope that helps:)
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