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rjkz [21]
3 years ago
9

A shoebox is covered with packing paper before being shipped. The paper cost $0.02 per square inch. How much will it cost to cov

er three pairs of shoes?
Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

Cost of packing 3 boxes = 3*(2LW + 2WH + 2LH) * 0.02 dollars

Step-by-step explanation:

Assume length of box = L in

height of box = H in

width of box = W in

surface area = (2LW + 2WH + 2LH) sq. in.

surface area of 3 boxes = 3*(2LW + 2WH + 2LH) sq.in.

Cost of packng one sq. in.= 0.02 dollars

Cost of packing 3 boxes = 3*(2LW + 2WH + 2LH) * 0.02 dollars

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Answer:

Median is 3

Step-by-step explanation:

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3 years ago
What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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3 years ago
Is the square of 4 a rational number?
Natalka [10]

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Bo, 4.23 is not bigger than 4.3
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Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

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   By triangle sum theorem in ΔABD,

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    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
3 years ago
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