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2 years ago

B(1)=−7 b(n)=b(n−1)+12 Find the 4th term in the sequence.

Mathematics

1 answer:

astra-53 [7]2 years ago

6 0

Answer:

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

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noname [10]

<h2>Key Ideas</h2>

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2 years ago

20 ounces into pounds'

evablogger [386]

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2 years ago

Read 2 more answers

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$