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Sidana [21]
3 years ago
8

Chapter 1 quiz 1. form g. do you know how? write an algebraic expression for each phrase. 1. a number x plus 11.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0
For this case we have the following sentence:
 "a number x plus 11"
 We want to write this phrase as an algebraic expression.
 We have then:
 a number x: x
 plus: +
 11: 11
 The algebraic expression is:
 x + 11
 Answer:
 
a number x plus 11 is:
 
x + 11
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Help pls! Idk what to do with this one.
muminat

i have answers but im not sure if there correct but ill write them down anyway a.6 b.2,3,6,9 c.first of all its spelled dice not die and yes because it all equals 100:)

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3 years ago
As an estimation we are told £3 is €4.<br> Convert £18 to euros.
Yuri [45]

Answer:

€24

Step-by-step explanation:

We can use ratios to solve this.

3:4 = 18:x

Cross multiply: 3x = 18*4

Divide: x = 18*4/3

Simplify: x = 6*4 = 24

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2 years ago
Can you explain with steps
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Answer:

Yep

1. Click ask question at the top

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Step-by-step explanation:

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3 years ago
PLEASE HELP!! <br> Factor completely: x2 + 6x + 8
Harman [31]
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3 years ago
Read 2 more answers
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
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