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3 years ago

Which line is parallel to the line given below?

Mathematics

2 answers:

vichka [17]3 years ago

7 0

Answer:

Step-by-step explanation:

2x+5y=-52...............

7nadin3 [17]3 years ago

6 0

The answer would be B 2x+5y=-52

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Is a= a, b = — 4<br> One solution, no solution or infinite solution

Sphinxa [80]

Answer: Infinite

Step-by-step explanation:

4 0

2 years ago

lauren spent $3.26 for lunch on Tuesday she spent $1.98 on Wednesday and $2.74 on Thursday list the price in ascending order

solmaris [256]

Answer:

1.98, 7.74, 3.26

Step-by-step explanation:

I listed them from Smalest to largest 1.98 being samller than 2.74 and 2.74 being smaller than 3.26.

Hope this helped :)

7 0

3 years ago

Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

Recall that

$\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}$

which converges everywhere. Then by substitution,

$\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}$

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

$f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}$

(starting at $n=1$ because the summand is 0 when $n=0$ )

b. Naturally, the differentiated series represents

$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

$-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)$

c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

3 0

3 years ago

9 + 3x - 8<br> can you simplify ?

n200080 [17]

Answer:

3x+1

Step-by-step explanation:

9+3x-8

9-8+3x

1+3x

4 0

3 years ago

Read 2 more answers

Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, space, c, m. He wanted his balloon to be

jonny [76]

The original volume of the balloon is given by:
V1 = (4/3) * (pi) * (r ^ 3)
Where,
r: radius of the sphere.
Substituting values:
V1 = (4/3) * (pi) * (1 ^ 3)
V1 = (4/3) * (pi) * (1)
Then, the volume of the current sphere is:
V2 = (4/3) * (pi) * ((1 + 2 * (1)) ^ 3)
V2 = (4/3) * (pi) * ((1 + 2) ^ 3)
V2 = (4/3) * (pi) * ((3) ^ 3)
V2 = (4/3) * (pi) * (27)
The relation of volumes is:
V2 / V1 = ((4/3) * (pi) * (27)) / ((4/3) * (pi) * (1))
V2 / V1 = 27/1
Answer:
The ratio of the current volume of the balloon to the original volume of the balloon is:
27: 1

6 0

3 years ago

Read 2 more answers