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3 years ago

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Which linear function has the steepest slope? On a coordinate plane, a line goes through points (0, 1) and (1, negative 2). A 2-

column table with 4 rows. Column 1 is labeled x with entries 3, 6, 9, 12. Column 2 is labeled y with entries 10, 13, 16, 19. On a coordinate plane, a line goes through points (0, negative 2) and (1, 0). A 2-column table with 4 rows. Column 1 is labeled x with entries 2, 4, 6, 8. Column 2 is labeled y with entries negative 4, negative 12, negative 20, negative 28.

2 answers:

Arada [10]3 years ago

6 0

Answer:

A is the answer

Step-by-step explanation:

did it on edge.2020

hope I helped :))

Yuri [45]3 years ago

3 0

Answer:

D

Step-by-step explanation:

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N divide by 1.6=5<br><br><br><br> Help

Bogdan [553]

8 maybe? I’m really not sure but I just did 5x1.6

7 0

3 years ago

Read 2 more answers

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

<u>case A)</u> point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

<u>case B)</u> point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

<u>case C)</u> point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

<u>case D)</u> point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

3 0

4 years ago

Read 2 more answers

andreev551 [17]

Answer:

A. y = 80x

B. g(x) = 80x

C. To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

Step-by-step explanation:

Part A:

To write an equation, use y= mx where m is the slope, x is the number of days, and y is the rent cost.

x and y remain the same in the equation.

To find m, use the slope formula with (5,465) and (7, 625).

$m=\frac{y_2-y_1}{x_2-x_1}= \frac{625-465}{7-5} =\frac{160}{2} =80$

It costs $80 a day.

The equation is y = 80x.

Part B:

Function notation replaces Y as g(x). So the equation is g(x) = 80x.

Part C:

To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

6 0

3 years ago

Need help ASAP!!!!! I WILL GIVE THE MOST BRAINLIEST TO THE FIRST PERSON THAT ANSWERS

lys-0071 [83]

Answer:

$x^2 + 10x + y^2 -4y + -7 = 0$

Step-by-step explanation:

For any circle point with coordinate of center (a,b) and radius r

equation of circle is given by

$(x-a)^2 + (y-b)^2 = r^2$

_______________________________________

Given

coordinate of center = (-5,2)

radius = 6

thus, equation of circle can be written by substituting a and b with (-5 ,2) and r =6 as shown below

$(x-a)^2 + (y-b)^2 = r^2\\(x-(-5))^2 + (y-2)^2 = 6^2\\x^2 + 10x + 25 + y^2 -4y + 4 = 36\\=>x^2 + 10x + y^2 -4y + 29 = 36\\=>x^2 + 10x + y^2 -4y + 29 -36 = 36 -36\\=>x^2 + 10x + y^2 -4y + -7 = 0$

Thus, equation of circle is $x^2 + 10x + y^2 -4y + -7 = 0$

3 0

3 years ago

What is the area of the shaded region?

IRINA_888 [86]

20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20

3 0

3 years ago