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4 years ago

Pair the equivalent fractions.

Mathematics

1 answer:

djverab [1.8K]4 years ago

3 0

Answer:

1. c 2. a 3. b

Step-by-step explanation:

The best way to prove these results are the right ones is by multiplying diagonally :

1. 1/3 = 4/12 -----> 1 . 12 = 12 ; 3 . 4 =12

2. 1/2 = 3/6 ------> 1 . 6 = 6 ; 2 . 3 = 6

3. 2/5 = 6/15 -----> 2 . 15 = 30 ; 5 . 6 = 30

The results of the multiplications must be the same if the fractions are equivalent.

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The answer is D) 12

Step-by-step explanation:

Multiple 4 by 3

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3 years ago

3 of 5 What is the nth term rule of the linear sequence below? 13,7,1, -5, -11, ... © T=

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The nth term is 6 .

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3 years ago

How many 2s are 120

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Step-by-step explanation:

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3 years ago

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Modeling Real-World Problems with Composite Functions

taurus [48]

Answer:

The third option: (f°g)(x)=1.07(0.65x)=06955x

Step-by-step explanation:

The reason I chose this is because 0.65x is the discount price. That's because 35% off is the same as 1.00-0.35 which equals 0.65. After that you would multiply that discount price by 1.07 because you want the 7% sales tax added on to the discount price. Therefore, I would choose the third option as my answer.

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3 years ago

(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)

tia_tia [17]

Answer:

$(4x-9)^2*(2x^2+2x+1)^2$

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

] (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1 Multiply (4x-9) by (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (4x-9) and the exponents are :

1 , as (4x-9) is the same number as (4x-9)1

and 1 , as (4x-9) is the same number as (4x-9)1

The product is therefore, (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1 Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2 Multiply (2x2+2x+1) by (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (2x2+2x+1) and the exponents are :

1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

and 1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

The product is therefore, (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

(4x - 9)2 • (2x2 + 2x + 1)2

6 0

3 years ago