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2 years ago

Graph a quadratic function with a vertex at (2, -3) with a = 3.

Mathematics

1 answer:

Alina [70]2 years ago

8 0

Answer:

bottom one

Step-by-step explanation:

use (x , y)

the top one is -3,2

the bottom one is 2,-3

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fgiga [73]

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2 years ago

Which values of xwould make a polynomial equal to zero if the factors of the

MariettaO [177]

9514 1404 393

Answer:

C. -6 and -9

Step-by-step explanation:

For the polynomial to be zero, one or more of the factors must be zero. For the factors to be zero, we require ...

x +6 = 0

x = -6 . . . . . . subtract 6 from both sides of the equation

and likewise, ...

x +9 = 0

x = -9 . . . . . . subtract 9 from both sides of the equation

x = -6 or -9 will make the polynomial zero.

4 0

2 years ago

Pls help if I don’t finish today mom will hurt me

kherson [118]

Answer:

We conclude that:

g(10) = 8

Step-by-step explanation:

First, we need to clear some concepts on how to fetch input and output from the function graph.

Determining the y-intercept:

We know that the y-intercept of the graph function can be determined by setting x = 0 and determining the corresponding y-value.

From the graph it is clear that x = 0, the value of y = 5. In other words, the graph intersects the y-axis at y = 5.

Therefore, the y-intercept of the graph is (0, 5).

Thus,

g(0) = 5

Determining the x-intercept:

We know that the x-intercept of the graph function can be determined by setting y = 0 and determining the corresponding x-value.

From the graph, it is clear that y = 0, the value of x = -10. In other words, the graph intersects the x-axis at x = -10.

Therefore, the x-intercept of the graph is (-10, 0).

Thus,

g(-10) = 0

Determining g(10):

From the graph, it is clearly visible that at x = 10, the value of the function output y = 8.

In other words,

at x = 10, g(10) = 8

Therefore, we conclude that:

g(10) = 8

5 0

3 years ago

A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.

Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}$

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}$

6 0

3 years ago

Two bags with 3 oranges in each bag is the same amount as 3 bags with 2 oranges in each bag. Which property of multiplication do

kodGreya [7K]

Answer:

Commutative Property

Step-by-step explanation:

The property of multiplication that is being demonstrated is known as Commutative Property. This property basically shows that when multiplying two numbers the actual order in which they are multiplied does not matter and does not affect the result at all. For example, the in this scenario to get the total number of oranges we have to multiply the number of bags by the number of oranges in each bag, but whatever way we do this they equal the same

2 bags * 3 oranges per bag = 6 oranges

3 bags * 2 oranges per bag = 6 oranges

Therefore,

2 * 3 = 3 * 2

7 0

3 years ago