We want to write
![\frac{\sqrt[]{5}+1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B%5D%7B5%7D%2B1%7D%7B2%7D)
as decimal, doing it on a calculator we have
![\frac{\sqrt[]{5}+1}{2}=1.61803398875](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B%5D%7B5%7D%2B1%7D%7B2%7D%3D1.61803398875)
But we only need three decimal places, then the result is
![\frac{\sqrt[]{5}+1}{2}=1.618](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B%5D%7B5%7D%2B1%7D%7B2%7D%3D1.618)
Answer:
C. 3.131131113…
Step-by-step explanation:
Irrational numbers cannot be written as a ratio of two integers and irrational numbers can have decimal that goes on forever without repeating
Answer:
Step-by-step explanation:ghjhe
Answer:
11.43
Step-by-step explanation:
10 divided by 7/8
Set the expression:
(10/(7/8))
To solve, flip the denominator fraction, and make the division into multiplication:
((10 x 8)/7)
Multiply across, then divide:
(80)/7
Divide:
80/7 = 11.43 (rounded)
11.43 is your answer.
~
Answer:
In the year 2010, the population of the city was 175,000
Step-by-step explanation:
If we rewrote this as a linear expression in standard form (it is linear, btw), it would look like this:

The rate of change, the slope of this line, is 11/2. If the year 2010 is our time zero (in other words, we start the clock at that year), then 0 time has gone by in the year 2010. In the year 2011, t = 1 (one year goes by from 2010 to 2011); in the year 2012, t = 2 (two years have gone by from 2010 to 2012), etc. If we plug in a 0 for t we get that y = 175,000. That is our y-intercept, which also serves to give us the starting amount of something time-related when NO time has gone by.