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frozen [14]
3 years ago
13

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be

considered independent of the other days. What is the probability that Sasha's first delay due to traffic will occur after the fifth day of travel to work?
Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

0.3277 = 32.77%

Step-by-step explanation:

If we want the probability for Sasha being late after the fifth day, we need that in the first five days she is not late, which has a probability of 1 - 0.2 = 0.8

So, multiplying the probability for each day, we have that:

P = 0.8 * 0.8 * 0.8 * 0.8 * 0.8 = 0.3277 = 32.77%

So we have a probability of 32.77% that Sasha's first delay will occur after the fifth day.

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Answer:

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Step-by-step explanation:

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There is a total of 15 questions in the test so we can use the formula for a binomial distribution with parameters n = 15, p = 0.5, q = 0.5

a)  If he needs to score 10 or more correct to pass, what is the probability that he will fail the exam?

To find this probability we will need to find the probability:

P ( X < 10) or

(1 -  P (x ≥10))

Remember that the formula for a binomial distribution is:

P(x) = \left[\begin{array}{ccc}n\\x\end{array}\right] p^{x} q^{n-x}

We can solve this by using the parameters given before and make x = 10, 11, 12, 13, 14, 15 and use the formula:

P(he fails the exam) = 1 - P (x≥10)

= 1 - (P(x=10) + P(x=11) + P(x=12) + P(x=13) + P(x=14) + P(x=15))

= 0.1509

b) Find the probability that he answers 6 to 11 inclusive)

We're going to use the same formula but we will do:

P (x = 6) + P (x = 7) + P (x = 8) + P (x = 9) + P (x = 10) + P (x = 11)

=0.1527 + .1964 + .1964 + 0.1527 + 0.0916 + 0.0416

= 0.8314

Therefore the probability that he answers 6 to 11 inclusive is 0.8314

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