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ZanzabumX [31]
2 years ago
14

Marta has 8 yellow ribbons what are 2 different ways she can place the ribbons on her door or wall write two different addition

equations
Mathematics
1 answer:
Drupady [299]2 years ago
7 0
One way she can place the ribbons is to place them in groups of 8/2=4, making 4+4=8 ribbons (2 groups because 8/4=2). Next, she can put them in groups of 2 (we can make it out of only 2 if we want since 2 is a factor) to get 8/2=4 groups of 2 and 2+2+2+2=8
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10

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Answer:

(a) B

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       0 = 0

Since we get down to 0 = 0, which is always true, we know that we cannot determine the cost of each ticket because there is more than one solution (infinitely many, actually). The answer is B.

(b) Our equation from this, if we still use t and p, is:

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5t + 4p = 82

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Subtract the second from the first:

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5t + 4p = 82

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2 years ago
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Answer:

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