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ZanzabumX [31]
3 years ago
14

Marta has 8 yellow ribbons what are 2 different ways she can place the ribbons on her door or wall write two different addition

equations
Mathematics
1 answer:
Drupady [299]3 years ago
7 0
One way she can place the ribbons is to place them in groups of 8/2=4, making 4+4=8 ribbons (2 groups because 8/4=2). Next, she can put them in groups of 2 (we can make it out of only 2 if we want since 2 is a factor) to get 8/2=4 groups of 2 and 2+2+2+2=8
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Martha baked 18 cupcakes .
velikii [3]

Answer:

66.67%

Step-by-step explanation:

\frac{12}{18} \times 100\\\\= \frac{1200}{18}\\ \\=66.67\%

7 0
3 years ago
Select the correct answer from each drop-down menu. In the figure, . Angles are congruent . ∠GAC ≅ ∠AFE because they are corresp
Hoochie [10]

Answer:

∠GAC ≅ ∠HFD by the Property of Congruence.

Step-by-step explanation:

I'm going to be honest the question is a little confusing cause of the beginning, but if you're looking for which angles are actually congruent it's ∠GAC ≅ ∠HFD

8 0
2 years ago
What percent of the bottle of apple juice is water?
Anettt [7]

percent of water is: 32/80*100= 40%

5 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
2 years ago
FIRST TO ANSWER GETS BRAINLY<br> Subtract and reduce to lowest terms:4 and 1/7 minuse 2 and 4/7
yan [13]

Answer:

It is 1  4/7

Step-by-step explanation:

7 0
2 years ago
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