Diameter=16mm, so the radius is 8. The formula for volume of a cylinder is the area of the base times height, or v=πr²h.
Substituting the values in, we get π(8²)(5.7), which gives us roughly 1146mm^3.
Answer:
-y^4+4y
Step-by-step explanation:
Answer:
You have to use PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction), and solve in that order. Your question is:
2 + 32 ⋅ (3 − 1)
First, solve the Parentheses part of the question. 3-1 is 2. Your question is now:
2+32*2
Now, solve the multiplication part of the question. 32*2 is 64. Your question is now:
2+64
This is now an easy problem to solve.
The answer is 66.
Hope this helps! :)
Answer:
2) 4/3
Step-by-step explanation:
(4^-3 * 3^4 * 4^2)/(3^5 * 4^-2)
4^-3 * 3^4 * 4^2 = 4^-1 * 3^4
(4^-1 * 3^4)/(4^-2 * 3^5)
(3^4)/(3^5) = 1/(3^5-4)
(4^(-1))/(4^-2 * 3^(5-4)
(4^-1)/(4^-2 * 3)
4^(-1 - (-2)) / (3)
-1 - (-2) = 1
4/3
Answer:
7. r = -5
8. x = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
r + 2 - 8r = -3 - 8r
<u>Step 2: Solve for </u><em><u>r</u></em>
- Combine like terms: -7r + 2 = -3 - 8r
- Add 8r to both sides: r + 2 = -3
- Subtract 2 on both sides: r = -5
<u>Step 3: Check</u>
<em>Plug in r into the original equation to verify it's a solution.</em>
- Substitute in <em>r</em>: -5 + 2 - 8(-5) = -3 - 8(-5)
- Multiply: -5 + 2 + 40 = -3 + 40
- Add: -3 + 40 = -3 + 40
- Add: 37 = 37
Here we see that 37 does indeed equal 37.
∴ r = -5 is a solution of the equation.
<u>Step 4: Define equation</u>
-4x = x + 5
<u>Step 5: Solve for </u><em><u>x</u></em>
- Subtract <em>x</em> on both sides: -5x = 5
- Divide -5 on both sides: x = -1
<u>Step 6: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: -4(-1) = -1 + 5
- Multiply: 4 = -1 + 5
- Add: 4 = 4
Here we see that 4 does indeed equal 4.
∴ x = -1 is a solution of the equation.
