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alisha [4.7K]
3 years ago
7

Find Four Numbers that form a geometric progression such that the second term is less than the first by 35, and the third term i

s greater than the fourth term by 560. (Note: there should be 3 different possible geometric sequences)
Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

  • -35/3, -140/3, - 560/3, -2240/3
  • 7, -28, 112, - 448  

Step-by-step explanation:

<u>The terms are:</u>

  • a₁, a₂, a₃, a₄

<u>Given:</u>

  • a₁ = a₂ + 35
  • a₃ = a₄ + 560

<u>Use the nth term formula:</u>

  • a₂ = a₁r
  • a₃ = a₁r²
  • a₄ = a₁r³

<u>Substitute:</u>

  • a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
  • a₁r² = a₁r³ + 560  ⇒ a₁(1 - r)r² = 560

<u>Divide the second equation by the first:</u>

  • r² = 560/35
  • r² = 16
  • r = √16
  • r = ± 4

<u>Use the first equation to find the first term:</u>

  • a₁( 1 ± 4) = 35
  • 1. a₁ = 35/-3 = -35/3
  • 2. a₁ = 35/5 = 7

<u>We have two sequences:</u>

r = 4

  • -35/3, -140/3, - 560/3, -2240/3

r = -4

  • 7, -28, 112, - 448  
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It is given that

X          Y

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<h3>What is an exponential function?</h3>

An exponential function is a relation of the form y = a^x, with the independent variable x ranging over the entire real number line as the exponent of a positive number a.

The y-value at -4 is 16 while the y-value at -1 is 2, a decrement of 1/8 times for an increment in x-value by 3

Again, the y-value at 2 is 0.25 while the y-value at 5 is 0.03125, a decrement of 1/8 times for an increment in x-value by 3.

In both cases, the rate of decrement is constant.

So we can say that this is an example of constant exponential decay.

We can also see this behavior from the attached graph.

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