Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
x=1
Step-by-step explanation:
5x + 2 = 3x + 4(2x - 1)
Distribute the 4
5x + 2 = 3x + 8x - 4
Combine like terms
5x + 2 = 11x - 4
Subtract 5x from each side
5x -5x + 2 = 11x - 5x - 4
2 = 6x-4
Add 4 to each side
2+4 = 6x-4+4
6 = 6x
Divide each side by 6
6/6 =6x/6
1= x
Answer:
A.Because ,center is (3,2)and point is (-2-3) .
and answer is (x-3)2+(y+2)2=52.
I’ve attached a photo, with the instructions. Hope it helps. If you have any questions don’t hesitate to ask
