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3 years ago

13

Cheyenne needs to cut a piece of paper so that she has exactly 1/3 of it. If the length of the paper is 11 inches, how long will

be the piece that she cuts?
3 and 1/3

2 and 1/3

3 and 2/3

2 and 2/3

2 answers:

Kipish [7]3 years ago

7 0

11* 1/3 = 11/3 =3 2/3

Choice c

frutty [35]3 years ago

4 0

Answer:

the correct anwser is 3 2/3

Step-by-step explanation:

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Darina [25.2K]

Answer:

B

Step-by-step explanation:

cos(a) is AC/AB and sin(B) is AC/AB

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3 years ago

What is 3 X 3/4 ? please help me

Vilka [71]

It is a multiplication question, just multiply: 3 x 3/4 = 9/4, now convert into mixed number and the answer is 2 1/4. I highly suggest learning how to solve simple math like this, it is quite easy.

8 0

3 years ago

Read 2 more answers

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago

One cup of grated, fresh Parmesan cheese weighs 3 ounces. How many cups of grated cheese can you expect to get from a 4.5-poun

Ksenya-84 [330]

Answer:

9 cups

Step-by-step explanation:

If one pound is equal to 2 cups, then you would multiply 2 by 4, which gives you 8. If one pound equals 2 cups, then half a pound equals 1 cup. So since we already have 8 cups, you just add one more cup, which gives you 9 cups total

SUMMARY: You can expect to get 9 cups of grated parmesan cheese from a 4.5-pound block.

5 0

2 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago