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Murrr4er [49]
3 years ago
13

How do I do orders of operations

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Step-by-step explanation:


Go from left to right doing any "A" or "S" as you find them. You can remember by saying "Please Excuse My Dear Aunt Sally".


(Brackets,Exponents,Divide,Multiply,Add,Subtract).

xeze [42]3 years ago
4 0

You can use PEMDAS to solve order of operations!

Which means, "Please Excuse My Dear Aunt Sally".

P= Parenthesis

E= Exponents

M= Multiplication

A= Addition

S= Subtraction

Here is an example of how to solve order of operations:

1×1+2-(12-1)

First: (12-1) = 11

Second: 1×1=1

Third: 1+2=3

Fourth: 3-11=8

The answer would be 8.



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Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

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Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

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The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

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So, The equation of required line is: \mathbf{5x-8y+34=0}

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