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Murrr4er [49]
3 years ago
13

How do I do orders of operations

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Step-by-step explanation:


Go from left to right doing any "A" or "S" as you find them. You can remember by saying "Please Excuse My Dear Aunt Sally".


(Brackets,Exponents,Divide,Multiply,Add,Subtract).

xeze [42]3 years ago
4 0

You can use PEMDAS to solve order of operations!

Which means, "Please Excuse My Dear Aunt Sally".

P= Parenthesis

E= Exponents

M= Multiplication

A= Addition

S= Subtraction

Here is an example of how to solve order of operations:

1×1+2-(12-1)

First: (12-1) = 11

Second: 1×1=1

Third: 1+2=3

Fourth: 3-11=8

The answer would be 8.



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Answer:

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Step-by-step explanation:

(hope this helps!)

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3 years ago
Jesse has a storage container in the shape of a right rectangular prism. The volume of the container is 43.875 cubic meters, the
Gnom [1K]

Answer:

The height is 2.25 meters.

Step-by-step explanation:

The volume of a right rectangular prism is the product of the length, width, and height. So it would be V=w*l*h.

Because you have been given the values of the volume, width, and length, you can plug in those values into the equation to find the height. It should look like this: 43.875=5 * 3.9 * h

Then you can divide both sides of the equation by 5 * 3.9.

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4 0
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Read 2 more answers
Describe the set of points z in the complex plane that satisfy the given equation; |z-2|=Re(z).
OLEGan [10]

Answer:

Parabola with vertex at point (1,0) that goes to the right (see attached diagram).

Step-by-step explanation:

Let the complex number z be

z=x+iy,

then

z-2=x+iy-2=(x-2)+iy\\ \\Re\ (z-2)=x-2\\ \\Im\ (z-2)=y\\ \\|z-2|=\sqrt{Re^2\ (z-2)+Im^2\ (z-2)}=\sqrt{(x-2)^2+y^2}

and

Re\ z=x

Thus,

\sqrt{(x-2)^2+y^2}=x

Square it:

(x-2)^2+y^2=x^2\\ \\x^2-4x+4+y^2=x^2\\ \\-4x+4+y^2=0\\ \\y^2=4x-4\\ \\y^2=4(x-1)

This is the equation of parabola with vertex at point (1,0) that goes to the right.

3 0
3 years ago
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