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IrinaVladis [17]
3 years ago
15

What is greater 35% or 2/5

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
Since 2/5 is equal to 40/100, or 40%, 2/5 is greater.
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If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)( ) = . The check of the polynomial division problem shows that the product of
azamat

Answer:

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

Step-by-step explanation:

Given

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

(x + 7) * (\ ) = [\ ]

Required

Complete the blanks

We have:

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

Rewrite as:

\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1

Cross multiply

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

8 0
3 years ago
Read 2 more answers
(9x^(2)+4x+2)-:(3x+x-2)
earnstyle [38]

Answer:

= - 9x2+4x+2/4x-2

Step-by-step explanation:

Remove parentheses

its blank we need to find a number

step 1: = -/4x-2 (9x2+4x+2)

step 2: multiply fractions and there is your answer

9x2+4x+2/4x-2

6 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
A bus driver pays all tolls, using only nickels and dimes, by throwing one coin at a time into the mechanical toll collector.
lutik1710 [3]

Answer: a) An = An-1 + An-2

b) 55ways

Step-by-step explanation:

a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.

Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that

An = 5n cents

Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;

An-1 = 5( n-1)

Case 2: using a dime which is two 5 cents, the number of ways is given as;

An-2 = 5(n-2)

Summing up the number of ways, we have

An = An-1 + An-2

From the relation,

If n= 0, Ao= 1

n =1, A1= 1

b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)

From the relation, we have that

Ao = 1

A1 = 1

An =An-1 + An-2

Ao = 1

A1 = 1

A2 = A1+Ao = 1+1= 2

A3 = A2 + A1 = 3

A4 = A3+A2=5

A5=A4+A3=8

A6=A5+A4=13

A7 =A6+A5 = 21

A8= A7+A6= 34

A9= A8+A7= 55

So there are 55ways to pay 45cents.

4 0
3 years ago
Find the common difference of the arithmetic<br> sequence 4, 10, 16,
DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

7 0
3 years ago
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