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Vlad1618 [11]
4 years ago
11

And can anyone do this?!!

Mathematics
1 answer:
Annette [7]4 years ago
6 0

a. The interest earned will be $36.

b. The account balance will be $336.

Step-by-step Explanation:

Step 1:

The initial amount put into the account was $300.

This account has an interest rate of 4% every year. So we must calculate how much 4% of $300 is.

4% of $300 = \frac{4}{100} (300) = 0.04 (300) = 12.

Step 2:

So for every year, the interest of $12 is added into the account. To calculate total interest we multiply this interest amount and the number of years.

So after 3 years = 3(12) = 36.

So account balance after 3 years 300+36 = 336.

So the interest earned is $36 and the account balance is $336 after three years.

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MaRussiya [10]

Answer:

8times 10 times 4 divided by 2 pplus 8 times 8 equals 64 + 80 = 144 m squared

Step-by-step explanation:

4 0
3 years ago
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What is the solution to the system of equations? Use the substitution method. {y=−2x+53x−4y=2
klio [65]

y =  - 2x + 53x - 4y = 2 \\  y  = 51x - 4y = 2 \\  > y = 51 x - 4y \\  > 51x - 4y = 2
y = 51x - 4y \\ 5y = 51x \\ y =  \frac{51}{5} x
Substitute 51/5x into
51x - 4( \frac{51}{5} x) = 2 \\ 51x - 40.8x = 2 \\ 10.2x = 2 \\ x = 2 \times  \frac{10}{102}  \\ x =  \frac{10}{51}  \: aka \: 0.196
Substitute that into
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8 0
3 years ago
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fomenos

Answer:

B

Step-by-step explanation:

4 0
3 years ago
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
Richard walks every day for exercise at a rate of 1 kilometer every 20 minutes.
OleMash [197]

Answer:

3000 meters

Step-by-step explanation:

1 kilometer = 1000 meters

1 kilometers = every 20 minutes

3× 1000 meters= 20 min ×3

3000 meters = 60 min/ 1 hour

7 0
3 years ago
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