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seropon [69]
3 years ago
12

Using the Pythagorean theorem, find the length of c if a = 14 * the square root of 3 and b = 34

Mathematics
1 answer:
ANEK [815]3 years ago
5 0

If c is the hypotenuse, we have

c=\sqrt{a^2+b^2}=\sqrt{(14\sqrt{3})^2+34^2}=\sqrt{588+1156}=\sqrt{1744}

If instead b is the hypothenuse, you have

c=\sqrt{b^2-a^2}=\sqrt{1156-588}=\sqrt{568}

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<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B11x%2B2%3D0" id="TexFormula1" title="5x^{2} +11x+2=0" alt="5x^{2} +11x+2=0"
eimsori [14]

The solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the solution to the quadratic equation?</h3>

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, the quadratic equation is given as

5x^2 + 11x + 2 = 0

Using the form of the quadratic equation y = ax^2 + bx + c, we have

a = 5, b = 11 and c = 2

The quadratic equation can be solved using the following formula

x = (-b ± √(b^2 - 4ac))/2a

Substitute the known values of a, b and c in the above equation

x = (-11 ± √(11^2 - 4 * 5 * 2))/2*2

Evaluate the exponent

x = (-11 ± √(121 - 4 * 5 * 2))/2*2

Evaluate the products

x = (-11 ± √(121 - 40))/4

Evaluate the sum

x = (-11 ± √(81))/4

Take the square root of 81

x = (-11 ± 9)/4

Expand

x = 1/4 * (-11 + 9) or x = 1/4 * (-11 - 9)

Evaluate the difference

x = 1/4 * -2 or x = 1/4 * -20

Evaluate the product

x = -1/2 or x = -5

Hence, the solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

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