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BARSIC [14]
3 years ago
8

Lol I’m still having trouble with Solve the system of linear equations using substitution. Can someone tell me what i did wrong

on this problem. X is one and I keep getting 0

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

first of all multiply the second eqn *6

so that we can cancel one

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crimeas [40]
It’s C. hope this helped and good luck !!
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3 years ago
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The area of a rectangular piece of cardboard is represented by
Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

A = wl

w(2w + 3) = 9

From this, we get that:

l = 2w + 3, A = 9

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

w(2w+3) = 9

2w^2 + 3w - 9 = 0

Thus a quadratic equation with a = 2, b = 3, c = -9

Then

\Delta = 3^2 - 4(2)(-9) = 81

w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5

w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

5 0
3 years ago
Curtis decided to go on a road trip to Canada. On the first day of his trip, he drove for 15 hours and traveled 1,005 miles. At
Radda [10]

Answer:

D

Step-by-step explanation:

1,005 / 15 = 67

3 0
3 years ago
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Is there a photo with this
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If g(x)= 2x-1, and h(x)= square root of x, find (goh)(9)
loris [4]
(goh) = 2(x^1/2)-1
(goh)(9) = 2(9^1/2)-1
= 2(3)-1
= 6-1
= 5
(goh)(9) = 5
5 0
3 years ago
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