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3 years ago

8

Solve the Inequality: m+16>8m+2

1 answer:

Setler [38]3 years ago

5 0

Answer:

m<2

Step-by-step explanation:

To get to this, you first need to move the variable to one side, so you could subtract m from both sides to make the equation 16>7m+2. Next, you subtract 2 from both sides to make the equation into 14>7m. Finally, you would divide 7 from both sides to get 2>m, or m<2.

Hope this helps!

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The senior class had a car wash to raise money for the senior trip. It cost them $35 for supplies. They washed 75 cars and charg

nikitadnepr [17]

Answer:

C. 75 • $6 - $35

Step-by-step explanation:

First, 75 times 6 needs to be in the expression to represent how much they raised from washing the 75 cars.

Then, 35 has to be subtracted because that was the cost of the supplies:

So, C is correct, 75 • $6 - $35

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4 years ago

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The graph of which function(s) will contain the point (4, 12)? y = x + 8 y = 3x y = 2x y = x + 6

Alex777 [14]

Answer:

y=x+8 and y=3x

Step-by-step explanation:

The Given point is (4,12)

now we can substitute the point in each of the function and check wether it lies on it or not.

A. y=x+8

substitute y=12,x=4

12=4+8=12 which is true

B. y=3x

substitute y=12,x=4

12=3*4=12 which is true

C. y=2x

substitute y=12,x=4

12=2*4=8 which is not true

D. y=x+6

substitute y=12,x=4

12=4+6=10 . which is not true

Therefore option A and B are correct.

4 0

4 years ago

What is a natural number?

WITCHER [35]

MAYBE 1 AND 0 ISA NATURAL NUMBER

5 0

3 years ago

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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

Read 2 more answers

. What's the common difference of the sequence 0, 5, 10, 15, 20, . . . ?

vichka [17]

Answer:

D. d = 5

Step-by-step explanation:

d = d² - d¹

= 5 - 0

= 5

d = d³ - d⁴

= 10 - 5

= 5

d = dⁿ - dⁿ-¹

6 0

3 years ago