Let h=height of water
Let r=radius of water surface
r/h=16/8 =2, so r=2h.
The volume of water is:
v=(1/3)×π×r²×h
=(1/3)×π×(2h)²×h
=4/3πh³
dv/dh=4πh^2
By chain rule:
dv/dt=dv/dh×dh/dt
but
dv/dt=4
thus:
4=(4πh)×dh/dt
dh/dt=4/(4πh²)
when h=6cm we have:
dh/dt=4/(4π6²)
=0.00884 cm³/min
Answer:
12
Step-by-step explanation:
3(9-h) is the equation used for this problem h=5
9-5=4 3x4=12
hope this helps!
You can use this formula: <span>vf^2=0+2(9.8)(M)
solve it out like so:
vf^2=0+2(9.8)(180)
vf^2=2(1764)
vf^2=3528
now, square both sides to cancel out the power of 2. you are left with:
about 59.4 m/s</span>
If I saw that correctly each position that's your multiplier so look at your 3rd position and make the 3 into a 30 so it would be 270 :)
