Answer:
8x^4+9x^3+4x-1
Step-by-step explanation:
(6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)
Group like terms
8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4
8x^4+9x^3+4x-1
Answer: 0.1
Step-by-step explanation:
Given
Bag-I has 2 blue,3 orange, 5 red
Bag-II has 4 Pink,10 blue, 6 brown
No of ways of choosing a blue marble from bag-I

Total no of ways of choosing a marble from bag-I

No of ways of choosing a blue marble from bag-II

Total no of ways of choosing a marble from bag-II

The probability that he will pull out a blue marble from each bag is


Since we aren't told the length of the 3rd bar, focus solely on the lengths of the first 2 bars. Add together their lengths: 1.15 cm + 3.92 cm = 5.07 cm.
Answer: Juanita shoots a series 5 free-throws. Let M = the number of free-throws she makes.
Step-by-step explanation: Khan
Answer =6
Step-by-step explanation: