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2 years ago

5

which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma

ny? but this test us something else

1 answer:

slamgirl [31]2 years ago

8 0

The original expression is given by:
$( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}$
The correct way to rewrite the expression is given by:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
$
For this, we use two properties:

Associative property:
The way of grouping the factors does not change the result of the multiplication:
$\frac{2}{3}*(\frac{1}{5}*\frac{5}{2})$

Commutative property:
The order of the factors does not vary the product:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})$

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The ratio between the radius of the base and the height of the cylinder is 2:3.if its volume is 1617cm^3,the total surface area

zalisa [80]

The answer is 769.3 cm²

The volume of the cylinder is : V = π r² h
<span>The ratio between the radius of the base and the height of the cylinder is 2:3:
r/h = 2/3
h = 3/2r

V = 1617 cm
</span>π = 3.14

1617 = πr² * 3/2 r
1617 = πr³ * 3/2
1617 * 2/3 = πr³
1078 = πr³
r³ = 1078/π = 1078/3.14 = 343
r = ∛343 = 7 cm

h = 3/2r = 3/2 * 7 = 10.5 cm

The surface area of the cylinder is:
SA = 2πr² + 2πrh
= 2 * 3.14 * 7² + 2 * 3.14 * 7 * 10.5
= 307.72 + 461.58
= 769.3 cm²

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2 years ago

A maritime flag is shown. What is the area of the shaded part of the flag? Explain

Rom4ik [11]

Answer:

<em></em> $Area = 72in^2$ <em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate the Area:</em>

<em></em> $Area_1 = Length * Width$ <em></em>

<em></em> $Area_2 = 8in * (6in + 6in)$ <em></em>

<em></em> $Area_2 = 8in * 12in$ <em></em>

<em></em> $Area_1 = 96in^2$ <em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em> $Area_2 = \frac{1}{2} * base * height$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * (6in + 6in) * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 12in * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 48in^2$ <em></em>

<em></em> $Area_2 = 24in^2$ <em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em> $Area = Area_1 - Area_2$ <em></em>

<em></em> $Area = 96in^2 - 24in^2$ <em></em>

<em></em> $Area = 72in^2$ <em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0

2 years ago

I need the base and hight

iris [78.8K]

Answer:

Height = 5 and Base = 10

Step-by-step explanation:

The base of the parallelogram is twice the perpendicular height of the parallelogram. The area of the parallelogram is 50 cm².

Formula for area of parallelogram = base × height

Base = 2h

Height = h

∴ Area = 2h × h = 50

Solution:

2h × h = 50

2h² = 50

$\frac{2h^{2} }{2} = \frac{50}{2}$

h² = 25

$\sqrt{h^{2} } = \sqrt{25}$

h = 5

∴ height = 5 and base = 2(5) = 10

4 0

2 years ago

Reflect the triangle (-2,-2) (-6,-8) (-8,-8) over the x-axis. What are the new vertices?

Inessa [10]

Reflecting across the x axis changes the y value to the opposite, but doesn't change the x value, so the new values are:
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2 years ago

Find the deriative dy/dx for y=x^2-2x/x^3+3

vaieri [72.5K]

Answer:

$\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

Step-by-step explanation:

So we want to find the derivative of the rational equation:

$y=\frac{x^2-2x}{x^3+3}$

First, recall the quotient rule:

$(\frac{f}{g})'=\frac{f'g-fg'}{g^2}$

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

$f=x^2-2x\\f'=2x-2$

$g=x^3+3\\g=3x^2$

So:

$\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'$

Use the above format:

$\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0

2 years ago