No. No. It is not linear because the slope has to be able to be plugged in to any x, y coordinates and be placed on the line.
In the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.
<h3>What is the triangle?</h3>
The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
In the first diagram:
The sum of the 5k + 20 and 7k + 40 is 180
5k + 20 + 7k + 40 = 180
12k + 60 = 180
12k = 180 -60
12k = 120
k = 10
In the second diagram:
The sum of the two interior angles is equal to the exterior angle.
40 + 12k + 10 = 8k + 80
4k = 30
k = 30/4 = 15/2
Thus, in the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.
Learn more about the triangle here:
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Answer:
<em>56</em>
Step-by-step explanation:
It seems like you have the answer already. but heres how its calculated.
so the missing number is 20 **cross multiply 100 and 3 to get 300 then divide 15 into 300 to get 20**
so the missing number is 50
**cross multiply 100 and 80 to get 8000 then divide 160<span> into 8000 to get 50**</span>
Answer:
y=3/4x-3
Step-by-step explanation:
Okay so to be parallel to an equation of another line, the line must have the same slope but a different y-intercept. First, you need to find the slope of the equation -3x+4y=4. The equation must be in y=mx+b format, so you first move -3x to the right by adding it on both sides, leaving you with 4y=3x+4. Next, you divide 4y by 4 in order to isolate y and do that on the other side. Now, you have y=3/4x+1.
To find the equation of the new line, you must put the point and slope into point slope form: y-y1=m(x-x1). In the point (4, 0), 4 would be x1 and 0 would be y1. so, the new equation is y-0=3/4 (x-4). now, distrubute the 3/4, leaving you with y=3/4x-3. This is correct since the slope remains the same in both equations with a different y-intercept. To check deeper, you could place point (4, 0) on a graph and then rise 3, run 4 until you get the line :) hope this helps
