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valkas [14]
3 years ago
7

Find the solution to the system of equations by using either graphing or substitution.

Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer: The answer is (-7,12)

Step-by-step explanation:

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Whats the scientific notation of 0.258
loris [4]
3 x 10^-5.
Explanation: You move the decimal point 5 places to the right, hence it <span>becomes 3 x 10 to the power of NEGATIVE 5 (moved 5 places right)</span>
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3 years ago
At Alan's auto shop, it takes him minutes to do an oil change and minutes to do a tire change. Let be the number of oil changes
kirill [66]

Complete question :

At Alan's auto shop, it takes him 9 minutes to do an oil change and 12 minutes to do a tire change. Let x be the number of oil changes he does. Let y be the number of tire changes he does. Using the values and variables given, write an inequality describing how many oil changes and tire changes Alan can do in less than an hour ( minutes).

Answer:

9x + 12y < 120

Step-by-step explanation:

Given that:

Time taken for oil change = 9 minutes

Time taken for tire change = 12 minutes

x = number of oil changes ; y = number of tire changes

Total hours = 1 hour = 60 minutes

Number of oil and Tyre changes possible in less than an hour

(Number of oil changes * time taken) + (number of tire changes * time taken) less than 60 minutes

9x + 12y < 120

8 0
3 years ago
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Find the prime factorization of 72.​
barxatty [35]

Answer:

2^3×3^2

and yh

Step-by-step explanation:

2×2×2×3×3

5 0
3 years ago
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Write a inequality to represent a number is at most two
Arturiano [62]

Answer:

x≤2

Step-by-step explanation:

8 0
2 years ago
$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent
photoshop1234 [79]

\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\&#10;\\&#10;\text{we know that the amount after t year when compounded is given by}\\&#10;\\&#10;A=P\left ( 1+\frac{r}{n} \right )^{nt}\\&#10;\\&#10;\text{here P is the principal amoount, so }P=7000,\\&#10;\\&#10;\text{r is the interest rate, }r=11\%=0.11\\&#10;\\&#10;\text{n is the number of times in a year, here semiannulay, so }n=2,\\&#10;\\&#10;\text{and t is the time, so }t=21\\&#10;\\&#10;\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\&#10;\\&#10;\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\&#10;\\&#10;\Rightarrow A=7000\left ( 1.055 \right )^{42}\\&#10;\\&#10;\Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

7 0
3 years ago
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