Radicals cannot exist as a denominator, so you would multiply both Sqrt96 and Sqrt8 by the Sqrt8, giving you Sqrt768 over 8 (since a sqrt times itself is the base number, in this case 8) then you would simplify Sqrt768 into 16 x Sqrt3, leaving you with 16xSqrt3 over 8. simplify into 2Sqrt3 by dividing.
Answer:
Step-by-step explanation:
Since, 
And 
Therefore, x = 5 and y = -3 will be the value of variables.
So think of |x+6| as a single object. Move the -6|x+6| to the left side and move the 8 to the right side to get 11|x+6| = 0. Then divide both sides by 11 to get |x+6| = 0 and in this instance the || can be dropped because +0 and -0 are the same. so x + 6 = 0 or x=-6
For point (1, 1): 1 = 4(1) - 3 = 4 - 3 = 1.
Therefore, the point (1, 1) is on the graph of the equation.
Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.
The graph of the equation is the set of all points that are solutions to the equation.
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