Select all statements that are true about the linear equation.

2 answers:

8 0

For point (1, 1): 1 = 4(1) - 3 = 4 - 3 = 1.
Therefore, the point (1, 1) is on the graph of the equation.

Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.

The graph of the equation is the set of all points that are solutions to the equation.

DochEvi [55]3 years ago

8 0

The correct answer for this question would be:

"The graph of the equation is the set of all points that are solutions to the equation."

"The point (1, 1) is on the graph of the equation."

And "The point (0, -3) is on the graph of the equation."

- I just took the test.

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Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.

Andreyy89

Let ${s_n}_{n\in\Bbb N}$ be a sequence that converges to $L$ . This means for any $\varepsilon>0$ , there is some $N$ such that $|s_n-L|$ for all $n>N$ . From this inequality we see that $|(s_n-L)-0|$ , so it follows that $s_n-L\to0$ .

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