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sergejj [24]
3 years ago
6

Select all statements that are true about the linear equation.

Mathematics
2 answers:
AveGali [126]3 years ago
8 0
For point (1, 1): 1 = 4(1) - 3 = 4 - 3 = 1.
Therefore, the point (1, 1) is on the graph of the equation.

Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.

The graph of the equation is the set of all points that are solutions to the equation.

DochEvi [55]3 years ago
8 0

The correct answer for this question would be:

"The graph of the equation is the set of all points that are solutions to the equation."

"The point (1, 1) is on the graph of the equation."

And "The point (0, -3) is on the graph of the equation."

- I just took the test.

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Translate 7 units right and units up​
Fantom [35]

Answer:

point G : (7,4)

point F : (7,1)

point J : (2,4)

point  H: (5,4)

Step-by-steWhen you translate you take each point and move it how many units it asks you to move. In this problen you move each point 7 units to the right and 9 units up to get your answer.

8 0
3 years ago
A relation is what in math
Kisachek [45]
A relation is a relationship between sets of values. In math, the relation is between the x-values and y-values of ordered pairs. The set of all x-values is called the domain, and the set of all y-values is called the range.
6 0
4 years ago
Read 2 more answers
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x, y =
Tema [17]

Answer:

Volume = π [ 2/3 - 12/2].

Step-by-step explanation:

So, in this question we are asked to find or Calculate for or determine the value of volume v of the solid obtained by rotating the region bonded by the given curves about the specified lines = ? (Unknown). In addition, we are given that y = x, y = x , so, about x = 3.

Volume = π ∫ [ (3 - y)^2 - (3 - y)^2 ] dy.

(Taking 0 and 1 as the lower and upper limit).

Volume = π ∫ 9 - 6y + y^2 - 9 - 6y + y^2 dy.

(Taking 0 and 1 as the lower and upper limit).

Volume = π ∫ 2y^2 - 12y dy.

(Taking 0 and 1 as the lower and upper limit).

(Solving the quadratic equation above, we have; Roots: -6, 0

Root Pair: -3 ± 3

Factored: f(x) = 2(x + 6)x)

Also,

Volume = π [ 2y^3 / 3 - 12y2/2]

Volume = π [ 2/3 - 12/2] cubic units.

3 0
3 years ago
Write a polynomial expression, in simplified form, that represents the AREA of the blanket and use the expression to evaluate th
pochemuha

Answer:

Polynomial expression that represents the area of blanket:

A(x)=(6x^2+5x-21)cm^2

If x=2: A(2)=13cm^2  

Step-by-step explanation:

The area of the rectangle can be calculated with the formula:

A=lw

Being l the lenght of the rectangle and w the width of the rectangle.

In this case, the lenght and the width are represented with:

l=(3x+7)cm

w=(2x-3)cm

Substitute them into  A=lw:

 A(x)=(3x+7)(2x-3)

Then:

Use Distributive property (Remember the Product of powers property: b^a*b^c=b^{(a+c)} ):

A(x)=(3x+7)(2x-3)\\A(x)=6x^2-9x+14x-21

Add like terms:

A(x)=(6x^2+5x-21)cm^2 (Simplied form)

Evaluate x=2:

A(2)=(6(2)^2+5(2)-21)cm^2\\A(2)=(6(4)+10-21)cm^2\\A(2)=(24-11)cm^2\\A(2)=13cm^2

6 0
4 years ago
Points 2
jonny [76]

Answer:

a = -1,6 b = 1,11 c = 4,11 .

4 0
3 years ago
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