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MissTica
3 years ago
11

Which of these ordered pairs could not be a dilation of (-2, 6)?

Mathematics
1 answer:
algol [13]3 years ago
7 0
Look at your answer choices, most of them could be proportional.. Now if you look at the rest of your answer choices you can see that the only one that doesn't reduce or increase like that is C. 
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Mary runs 5 miles in 1.25 hours. How many miles does she run in 1 hour?<br> HELP PLSSS
ICE Princess25 [194]

Answer:

She runs 4 miles in one hour

Step-by-step explanation:

5 divided by 1.25=4

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3 years ago
One number is 16 less than 4 times the second number. Their sum is 29. Find the numbers.
aleksklad [387]

Answer:

20,9

Step-by-step explanation:

this is how I did=x=1st, y=2nd; x=4y-16 and x+y=29; thus 4y-16+y=29; 5y-16=29; 5y=45; y=45/5=9, once you know y=9, put in equation, 4y-16=×, (4*9)-16=x, 36-16=x, 20=x

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2 years ago
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erma4kov [3.2K]
This is the answer to it

7 0
3 years ago
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
Gnom [1K]

<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

7 0
2 years ago
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