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4 years ago

18 divided by tan 30

Mathematics

1 answer:

Arlecino [84]4 years ago

6 0

Answer:

18cot(30) or nearly -2,81016

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Please Help Me On These Questions!!!!!! I need Help!!!!!

melisa1 [442]

1. This is one confusing question... But here is what I did
x = 2y + 1
y = $3y^{2}$ + 2x

So plug in Y to solve for X
x = 2 ( $3y^{2}$ + 2x) + 1
x = $-2y^{2}$ - $\frac{1}{3}$
Not sure if that's completely correct, but I'm positive I didn't make any mistakes...

5. You have to find the multiples of 60 so...

1 60
2 30
3 20
4 15
5 12 <---

7 = 12 - 5

4 0

3 years ago

Solve by elimination: 2x + 4y = 34 x+4y = 27 A (7,-5) B (6,6) (7,5) (5,7)

julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0

3 years ago

Read 2 more answers

in a fish tank 8/11 of the fish have red stripes on them. If 16 of the fish have red stripes,how many total fish are in the tank

Margarita [4]

There are 22 total fish in the tank because 8 got doubled so 11 would also have to get doubled

6 0

4 years ago

Read 2 more answers

Eight minus the product of 2 and a number

faltersainse [42]

Answer:

8-2x+y

Step-by-step explanation:

8-2x+y

8 0

4 years ago

Read 2 more answers

Aria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there wer

denpristay [2]

Answer:

8,800,000cars

Step-by-step explanation:

Given the initial amount of cars = 80,000,000

If there is 10 % increase in the first year;

Increment = 10% of 80,000,000

Increment = 0.1 * 80,000,000

Increment = 8,000,000

Amount of car in year 2 = 80million + 8million = 88million

Year3;

Amount of car in year 3 = 88,000,000+(10%of88million)

Amount of car in year 3 = 88,000,000+8,800,000

Amount of car in year 3 =96,800,000

Differences in the number of cars = 96,800,000 - 88,000,000

Differences in the number of cars = 8,800,000cars

Hence there are 8,800,000cars in years 3 than year 2

7 0

3 years ago