All categories

3 years ago

5a. A salad bar has five kinds of salad. In how many different ways can you choose two different salads from five?

Mathematics

1 answer:

Charra [1.4K]3 years ago

6 0

Answer:

a) 10 salads

b) 5 Choose 2 and 5 Choose 3 result in the same amount

Step-by-step explanation:

a) ₅C₂ = 5! / (5-2)! 2!

= 5! / 3! 2!

= (5 × 4) / 2

= 10 salads

b) ₅C₃ = 5! / (5-3)! 3!

= 5! / 2! 3!

= (5 × 4) / 2

= 10

You might be interested in

C.J can shoot 36 shots in 3 minutes enter the number of shots C.J can shoot in 1 minute

Anna007 [38]

Answer:

he can shoot 12 shots in 1minute

Step-by-step explanation:

3minutes = 36 shots

1 minute= 36 divided by 3 which is equal to 12

4 0

2 years ago

Order of operations, step by step 56-12 / 6+4

icang [17]

Answer:

Step-by-step explanation:

Order of operations:

Parentheses
Exponents
Multiplication-Division
Addition-Subtraction

Solve:

56-12 / 6+4

56 - (12/6) +4 { No Multiplication but do have Division} (12/6 = 2)

56 - 2 + 4 {Subtraction ⇒ 56-2 = 54}

54 + 4 { Addition ⇒ 54 + 4 = 58}

Answer = 58

[RevyBreeze]

7 0

2 years ago

A seed company planted a floral mosaic of a national flag. The perimeter of flag is 2,340 ft determine the flag’s width and leng

Natali5045456 [20]

Answer:

Width: 450 feet

Length: 720 feet

Step-by-step explanation:

So we start with the equation to find the perimeter -

2l + 2w = p

l = length

w = width

p = perimeter

We insert the 2,340 ft as the perimeter -

2l + 2w = 2,340 ft

Now we find another equation for the "length is 270 ft greater than width" -

l = 270 ft + w

Using substitution, we substitute the y in the first equation with 270 ft + w -

2 (270 ft + w) + 2w = 2,340 ft

540 ft + 2w + 2w = 2,340 ft

540 ft + 4w = 2,340 ft

4w = 2,340 ft - 540 ft

4w = 1,800 ft

w = 1,800 ft / 4

w = 450 ft

Now to find the width we substitute the w with 450 ft -

l = 270 ft + w

l = 270 ft + 450 ft

l = 720 ft

Check -

2 * 720 ft + 2 * 450 ft = 2,340 ft

1,440 ft + 900 ft = 2,340 ft

2,340 ft = 2,340 ft (Correct)

3 0

3 years ago

What is the equation for the plane illustrated below?

TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

$a\cdot x + b\cdot y + c\cdot z = d$

Where:

$x$ , $y$ , $z$ - Orthogonal inputs.

$a$ , $b$ , $c$ , $d$ - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0), (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

$y = m\cdot x + b$

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - x-Intercept, dimensionless.

If $x_{1} = 2$ , $y_{1} = 0$ , $x_{2} = 0$ and $y_{2} = 2$ , then:

Slope

$m = \frac{2-0}{0-2}$

$m = -1$

x-Intercept

$b = y_{1} - m\cdot x_{1}$

$b = 0 -(-1)\cdot (2)$

$b = 2$

The equation of the line in the xy-plane is $y = -x+2$ or $x + y = 2$ , which is equivalent to $3\cdot x + 3\cdot y = 6$ .

yz-plane (0, 2, 0) and (0, 0, 3)

$z = m\cdot y + b$

$m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}$

Where:

$m$ - Slope, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

If $y_{1} = 2$ , $z_{1} = 0$ , $y_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

y-Intercept

$b = z_{1} - m\cdot y_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the yz-plane is $z = -\frac{3}{2}\cdot y+3$ or $3\cdot y + 2\cdot z = 6$ .

xz-plane (2, 0, 0) and (0, 0, 3)

$z = m\cdot x + b$

$m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - z-Intercept, dimensionless.

If $x_{1} = 2$ , $z_{1} = 0$ , $x_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

x-Intercept

$b = z_{1} - m\cdot x_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the xz-plane is $z = -\frac{3}{2}\cdot x+3$ or $3\cdot x + 2\cdot z = 6$

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

$a = 3$ , $b = 3$ , $c = 2$ , $d = 6$

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

8 0

3 years ago

Can some one solve for r please 15r-6r=36

myrzilka [38]

Answer:

R=4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers