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likoan [24]
2 years ago
12

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS

Mathematics
2 answers:
Verdich [7]2 years ago
6 0

Answer:

( -3, -5)

step-by-step explanation:

  • original coordinates of C: (0, -7)

translation vertically means change in y axis

translation horizontally means change in x axis

solve:

( 0 -3, -7 + 2)

( -3, -5)

Scrat [10]2 years ago
4 0
The answer would be (-3,-5) bc you move the C coordinate up 2 and to the left 3
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2.) Use the Slope Intercept Form of a line to find the equation of the line from point C to point D.
mezya [45]

First we need slope

  • C=(0,0)
  • D(7,12)

\\ \sf\longmapsto m=\dfrac{12-0}{7-0}

\\ \sf\longmapsto m=\dfrac{12}{7}

Put D co-ordinates on y=mx+b

\\ \sf\longmapsto 12=\dfrac{12}{7}(7)+b

\\ \sf\longmapsto 12=12+b

\\ \sf\longmapsto b=12-12

\\ \sf\longmapsto b=0

Now

slope intercept form.

\\ \sf\longmapsto y=\dfrac{12}{7}x

  • As b=0
8 0
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Turn everything into fractions. You can also combine like terms.

Step-by-step explanation:

5 0
3 years ago
In circle C, r = 32 units.
vlabodo [156]
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5 0
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What is Dr. Phil's First name?
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7 0
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Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

7 0
3 years ago
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