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AlekseyPX
3 years ago
9

3 3/15 write the fraction as a decimal

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
The answer is .2, your welcome, bit check with someone else first.
daser333 [38]3 years ago
4 0
3.2 . I don't really know how to explain this, but I need to write at least 20 characters to give you my answer.
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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
Assume the availability of a method named makeStars that can be passed a non-negative integer n and that returns a String of n a
kramer

Answer:b

Step-by-step explanation:

b

6 0
3 years ago
Help please. I need this in a few minutes
Ghella [55]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The graph below shows the number of new clients brought into Sunnydays Insurance Company. Why is the graph misleading?
Lera25 [3.4K]

The graph is misleading because the year’s interval is not constant. The first year to the second year, the gap is 1 year; in the second to the third year, the gap is 2; in the third to the fourth year is 4; and the fourth to the fifth year is 6.

8 0
3 years ago
A sports tournament has d teams. Each team has 16 players . Using, write an expression for total number of players in the tourna
Vilka [71]

Answer:

16d

Step-by-step explanation:

multiply 16 by d as there are 16 players for each team

8 0
3 years ago
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