1.<AFC
2.<AFD
3.<AFE
4.<AFB
#5, 6 and 7
m<BAE = 59
m<BAC + m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11
m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12
answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12
#8, 9 and 10
m<BAE = 130
m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20
m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35
answer
8.
m<BAC = 50
9.
m<CAD = 45
10.
m<DAE = 35
Answer:
slope = - 
Step-by-step explanation:
Parallel lines have equal slopes thus the slope of a parallel line will be equal to the slope of PQ
To calculate slope m use the slope formula
m = 
with (x₁, y₁ ) = P(- 2, 4) and (x₂, y₂ ) = Q(6, - 2)
m =
=
= - 
Answer:
slope of parral line is same as slope of line its 1
Answer:
1) 1 to 3
2) 1/3 B*H
Step-by-step explanation:
Answer:
1. c 2. a 3. e 4. d (this one i am not 100% sure on) 5. b 6. i believe is d
Step-by-step explanation: