Find the value of x in the isosceles triangle shown below
1 answer:
Answer:
22.18 = x
Step-by-step explanation:
a^2 + (b)^2 = (x/2)^2
a = sqrt(74)
b = 7
x/2 = ?
(74)[^1/2]^2 = 74
b^2 = 7^2 = 49
74 + 49 = (x/2)^2 Substitute into a^2 + b^2 = c^2
123 = (x/2)^2 Combine like terms
(123^0.5) = x/2 Take the square root of both sides.
11.09 = x/2 Multiply both sides by 2
11.09*2 = x
22.18 = x The full length of the base of the triangle is 22.18
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