Answer:
the answer of this question is 1/3
39/117 = 1/3
Hey there! I'm happy to help!
In the quadratic formula, the discriminant is square rooted. In this formula you have a ± before this radical. If the discriminant is positive, the solution can be either subtracting or adding the number, so there are 2 real solutions.
If it is 0, subtracting or adding are the same, so there will be just one solution.
You cannot have a negative square root. It is impossible with real numbers, so there are no real solutions.
I hope that this helps! Have a wonderful day! :D
Answer:
3 and 4
Step-by-step explanation:
Well to start we have to know that they are asking us, a factorized form of a quadratic expression
a quadratic expression is of the form
ax ^ 2 + bx + c
Now the factored form is as follows
a ( x - x1 ) ( x - x2 )
Next, let's look at each of the options
In this case we lack a term with x since if we solve we have a linear equation
1. 5(x+9)
5x + 45
In this case if we pay attention they are being subtracted instead of multiplying, so we will not get a quadratic function
2. (x+4) - (x+6)
-2
In this case we have everything we need, now let's try to solve
3. (x-1) (x-1)
x^2 - x - x + 1
x^2 - 2x + 1 quadratic function
In this case we have everything we need, now let's try to solve
4. (x-3) (x+2)
x^2 -3x +2x -6
x^2 -x - 6 quadratic function
In this case we have a quadratic function but we do not have it in its factored form since we can observe the x ^ 2
5. x^2 + 8x
Answer:
Answer should be x^9
Step-by-step explanation:
This equation looks really complicted, but it's actually much easier when you break it down! First, your going to multiply the fraction 3/2 by 6 - since one is a fraction, youre going to find the GCF, or Greatest Common Factor, and reduce it. The GCF in this equation is 2, so we eliminate the two from the fraction (making it just 3) and divide 6 by 2 (getting 3). Thus, we are left with (x^3)^3 -> 3 x 3 = 9. So we are left with x^9. I hope this helps!
