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3 years ago

Find the product of (3x − 4)(2x2 + 2x − 1).

Mathematics

2 answers:

alexira [117]3 years ago

6 0

Solve:

(3x − 4)(2x^2 + 2x − 1)

Simplify:

(3x − 4)(2x^2 + 2x − 1)

= (3x + −4)(2x^2 + 2x + −1)

= (3x)(2x^2) + (3x)(2x) + (3x)(−1) + (−4)(2x2) + (−4)(2x) + (−4)(−1)

= 6x^3 + 6x^2 − 3x − 8x^2 − 8x + 4

Answer = 6x^3 − 2x^2 − 11x + 4

Hope that helps!!!! : )

STALIN [3.7K]3 years ago

5 0

the answer to your question is -12

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Find the slope of the line joining the points (3,4) and (6,-1)

grandymaker [24]

Answer:

Step-by-step explanation:

(3,4) ; (6,-1)

slope = y₂ - y₁ / x₂-x₁

= -1 - 4 / 6-3

= -5/3

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3 years ago

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Solve 3/5=8/y. Round to the nearest tenth. 15.2 9.8 13.3 18.8

Sidana [21]

3/5 = 3/y
40 = 3y
Divide both by 3
Answer= 13.3

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4 years ago

Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (

valentinak56 [21]

Answer:

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4) and (5, 1, 0)

$A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]$

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

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= 1(-4) - 1(3) + 5(6)

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4 0

3 years ago

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3 years ago

For which function is f(x) equal to f^-1(x)?

Ilia_Sergeevich [38]

We will find the inverse of the given functions:
y = x + 2 / x-2
(x-2) y = x + 2
-2y + xy = x + 2
-2y + xy = x + 2
x (y - 1) = 2 + 2y
x (y - 1) = 2 (y + 1)
x = 2 (y + 1) / (y - 1)
f (x) ^ - 1 = 2 (x + 1) / (x - 1)
The inverse is different.
f (x) = x + 1 / x-1
y = x + 1 / x-1
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x = (y + 1) / (y - 1)
f (x) ^ - 1 = (x + 1) / (x - 1)
The inverse is the same.
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f (x) = x + 1 / x-1
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3 years ago

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