Please help, no links or i will report
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so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.
We have, Discriminant formula for finding roots:
Here,
- x is the root of the equation.
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
1) Given,
3x^2 - 2x - 1
Finding the discriminant,
➝ D = b^2 - 4ac
➝ D = (-2)^2 - 4 × 3 × (-1)
➝ D = 4 - (-12)
➝ D = 4 + 12
➝ D = 16
2) Solving by using Bhaskar formula,
❒ p(x) = x^2 + 5x + 6 = 0
So here,
❒ p(x) = x^2 + 2x + 1 = 0
So here,
❒ p(x) = x^2 - x - 20 = 0
So here,
❒ p(x) = x^2 - 3x - 4 = 0
So here,
<u>━━━━━━━━━━━━━━━━━━━━</u>