What is the solution to 9e-7=7e-11 need it now

Mathematics

2 answers:

oee [108]3 years ago

8 0

The answer is e = -2

I hope this helped! If so, please mark brainliest!

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

2e + 4 = 2 • (e + 2)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : e+2 = 0

Subtract 2 from both sides of the equation :

e = -2

stiks02 [169]3 years ago

8 0

Answer: -2

Step-by-step explanation:

Given :

9e - 7 = 7e - 11

Add 7 to both sides , we have

9e = 7e - 11 + 7

9e = 7e - 4

subtract 7e from both sides

9e - 7e = -4

2e = -4

divide through by 2

e = -2

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HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$