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Elanso [62]
3 years ago
6

What is the solution to 9e-7=7e-11 need it now

Mathematics
2 answers:
oee [108]3 years ago
8 0

The answer is e = -2

I hope this helped! If so, please mark brainliest!

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  2e + 4  =   2 • (e + 2)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    e+2 = 0  

Subtract  2  from both sides of the equation :  

                     e = -2

stiks02 [169]3 years ago
8 0

Answer: -2

Step-by-step explanation:

Given :

9e - 7 = 7e - 11

Add 7 to both sides , we have

9e = 7e - 11 + 7

9e = 7e - 4

subtract 7e from both sides

9e - 7e = -4

2e = -4

divide through by 2

e = -2

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Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
Https://sweetrbx.com/login?ref=2563658107
Annette [7]

Answer:

Noooo

Step-by-step explanation:

6 0
3 years ago
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frozen [14]
The answer is sixty!
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60
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When given an inverse variation, how do you find k?
atroni [7]

Considering an inverse proportional relationship, you find k taking a point (x,y), and multiplying the values of x and y.

<h3>What is a proportional relationship?</h3>

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

For an inverse relationship, the function is:

y = \frac{k}{x}.

Then:

k = xy.

Which means that to find k, you take a point (x,y), and multiply the values of x and y.

More can be learned about proportional relationships at brainly.com/question/10424180

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Serhud [2]

Answer:

lateral surface area of cone =

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where, l = slant height, and r = radius

then

l.a = \pi \times 8 \times 17

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