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cestrela7 [59]
3 years ago
6

7 squaerd - 5 squaerd dived by 34

Mathematics
1 answer:
allsm [11]3 years ago
4 0
49- 25 / 34 Solve this (sry I don't have a calculator with me but I hope this helped :)★)

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17-4(6-p) = -59 find the p
sdas [7]

Answer:

-13

Step-by-step explanation:

Have a nice day !

5 0
3 years ago
Match each scenario with the tax it is describing by putting the correct number next t
Anna [14]

Answer:

1) Yvonne buys gloves that cost $10.00. At the register, she must pay  $10.80. ⇒ EXCISE TAX  

2)Sasha bought a house last year. She just got a tax bill from the  county showing the value of her house and the amount of tax. ⇒ PROPERTY  TAX  

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8 0
3 years ago
Read 2 more answers
Estado tratando esto por mucho tiempo​
maksim [4K]

Answer:

1/2

Step-by-step explanation:

Paso Uno: \frac{5}{1}* \frac{5}{1} *\frac{5}{1}* \frac{5}{1} *\frac{5}{1}* 1/10= 5/10

Paso Dos: Simplificar:

5/5=1

10/5=2

Paso Tres: fracción es 1/2

6 0
3 years ago
During which months in 2005 was Fargos precipitation more than 20 mm below its long term average
nevsk [136]
I will send you a hopefully helpful link. https://www.ncdc.noaa.gov/sotc/national/201403
6 0
3 years ago
A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
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