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stiks02 [169]
3 years ago
11

Simplify 3xy - 9xy + 11y

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0
-6xy+11y
Shehshdhdhsbsvsvsvsvs
Aleonysh [2.5K]3 years ago
3 0

-y · (6x-11)

Hope that helps

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Sheryl spends ​$17 every week on cigarettes and spends ​$24 a month on dry cleaning. On an annual​ basis, the money spent on cig
Rzqust [24]

the correct question is

Compute the total cost per year of the following pair of expenses. Then complete the sentence: On an annual basis, the first set of expenses is _% of the second set of expenses.Sheryl spends $17 every week on cigarettes and spends $24 a month on dry cleaning.


we know that

1 year is equal to 52 weeks

1 year is equal to 12 months

To calculate:

$17 * 52 = $884

$24 * 12 = $288

then

884/288 = 3.0694 * 100 = 306.94%

<span>

</span>

therefore

<span>

</span>

the answer is

<span>306.94%</span>


8 0
4 years ago
Please help me<br><br> b minus 3/4 = 7/10
RoseWind [281]
B - 3/4 = 7/10
add 3/4 to both sides to isolate the b
b = 7/10 + 3/4
b = 28/40 + 30/40
b = 58/40
b = 1  18/40
b = 1   9/20
5 0
3 years ago
Read 2 more answers
Angle measures of a triangle are in the ratio 5:6::7. Find the measures of the triangle
Arturiano [62]

Answer:

(5×6)=30×7=140 the answer is 140

7 0
4 years ago
Advertisements for the Sylph Physical Fitness Center claim that completion of their course will result in a loss of weight (meas
MrMuchimi

Answer:

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

Step-by-step explanation:

The data given is

                        Mean                 Std Dev

Before            177.25                29.325

After              169.50                    22.431

Difference        7.75                    8.598

Hence d`=   7.75 and sd=   8.598

The 90% confidence interval for the difference in means for the paired observation is given by

d` ± t∝/2(n-1) *sd/√n

Here  t∝/2(n-1)=1.895  where n-1= 8-1= 7 d.f

and  ∝/2= 0.1/2=0.05

Putting the values

d` ± t∝/2(n-1) *sd/√n

7.75  ±1.895 *  8.598 /√8

 7.75  ± 5.7605

1.989 ,13.5105

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

3 0
3 years ago
What's the Discriminant of X^2-2X-15 ?
Nesterboy [21]
The discriminant is the  secion inside the double parenthasees [()] below in the quadratic formulat which is
x=\frac{-b+ \sqrt{[(b^{2}-4ac)]} }{2a}

the determinant determines or tells whether the answer is real or imaginary
if it is negative, then it is imaginary, if positive, then it is real
 so basically the discriminmant is b^{2}-4ac

so ax^2+bx+c
a=x^2-2x-15

a=1
b=-2
c=-15

subsitute
-2^{2}-4(1)(-15)=4-4(1)(-15)=4+60=64
the discriminant is (-2^{2}-4(1)(-15)) or 64
3 0
3 years ago
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