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Vikki [24]
2 years ago
7

Please answer this I will mark you plz plz​

Mathematics
2 answers:
STatiana [176]2 years ago
8 0

Answer:

y=120 degree z=120 degree and x=60degree

Step-by-step explanation:

y+60¤ =180¤(being straight line )

or,y=180¤-60¤

or,y=120¤

therefore y=120¤

Now z= 120¤ (being corresponding angle)

therefore z =120¤

here at last,

z+120=180 (being straight anngle)

or, z=60¤

therefore z =60¤

( ¤): degree

OleMash [197]2 years ago
7 0

Answer:

don't know sorry......................

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Ty's brother earns $15 per hour. The store offers him a raise of 12%. How much is the raise in dollars
gizmo_the_mogwai [7]

Answer:

$1.80

Step-by-step explanation:

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3 years ago
1st<br> what does this situation refers to?
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3 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
PLEASE HELP
lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


4 0
2 years ago
A right triangle with two congruent legs is always a 45-45-90 triangle.
saw5 [17]

Answer:

True

Step-by-step explanation:

I think this is a true or false question and this is a true statement.

6 0
3 years ago
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