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marshall27 [118]
3 years ago
8

1. What is the perimeter of the figure below. Simplify. 4x^3-5x 2x^3+6x 6x^3+x

Mathematics
1 answer:
____ [38]3 years ago
6 0

Answer:

12x^3+2x

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of its sides.

The sides in the triangle shown have lengths 2x^3+6x, 4x^3-5x, and 6x^3+x in no specific order.

Since its perimeter is given by the sum of its sides, the perimeter is equal to:

2x^3+6x+4x^3-5x+6x^3+x

Combine like terms:

\boxed{12x^3+2x}

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Please hurry I will mark you brainliest <br> Find the surface area
erastova [34]

Triangle area = 8 x 3/2

= 12

12 x 2 = 24cm^2 for 2 triangles

Height of rectangle must be found, so use pythag on triangle

a^2+ b^2 = c^2

16 + 9 =c^2

C=5

A= 5 x 12

= 60

60 x 3 triangles in total is 180cm^2

180cm^2 + 24cm^2 = 204cm^2

Ans: 204cm^2

4 0
2 years ago
Find the value of n<br><br> 6/n = 5/120
sleet_krkn [62]

Answer:

n = 144

Step-by-step explanation:

          6 / n = 5/120

         6 * 120 = 5*n

               5n = 6*120

               5n = 720

                 n = 720/5

                 n = 144

8 0
3 years ago
Read 2 more answers
2. What helps you to get the root of a number?​
xeze [42]

Answer:

Separate The Digits Into Pairs.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the converse of the conditional statement?
Natalija [7]

Answer:

If x+1 is odd, then x is even B

Step-by-step explanation:

Conditional: If p, then q

Converse: If q, then p

p= x being even

q, x+1 being odd.

5 0
3 years ago
A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati
I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

\frac{dT}{dt}=k*(T_r-T)

If we rearrange and integrate

\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}

We know that at time 0, the temperature of the drink was 52°F. Then we have:

T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20

We also know that at t=2, T=55°F

T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

7 0
3 years ago
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