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vodka [1.7K]
3 years ago
11

Two friends shop for fresh fruit. Jackson buys a watermelon for $6.35 and 4 pounds of cherries. Tim buys a pineapple for $4.25 a

nd 3 pounds of cherries Use the variable P to represent the price in dollars per pound of cherries. Write and simplify an expression to represent how much more Jackson spent.
Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

7.65 + 5p - (2.45 - 4p) =

7.65 + 5p - 2.45 + 4p =

5.20 + 9p <==

Step-by-step explanation:

hope dis helps mark me as brainliest pls!!!!!

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Answer:

The response that are true are:

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Since in linear function the rate of change is always equal as for a linear function we get a equation of line such that the slope is same.

  • On a graph, the function must be a straight line to be linear.

Liner means there is a straight line of the function.

( Also it need not be true that the independent variable increases by 1.

There may be change of some other quantity in independent variable )

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2 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

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P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

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