Answer:
X=60
Step-by-step explanation:
X fraction 2 - 5 = 25
X/2-5=25
X/2 =25+5
X/2=30
X=60
60 is the answer
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are blue-green-black.
Now the rest of the collection consists of
4 blue
4 green
2 black
and there's space for 2 more marbles in the case.
So the question really asks: "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"
-- Well, there are 10 marbles all together.
So the first one chosen can be any one of the 10,
and for each of those,
the second one can be any one of the remaining 9 .
Total number of ways to pick 2 out of the 10 = (10 x 9) = 90 ways.
-- BUT ... there are not nearly that many different combinations
to wind up with in the case.
The first of the two picks can be any one of the 3 colors,
and for each of those,
the second pick can also be any one of the 3 colors.
So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
For a
body moving with increasing acceleration, the graph will be in the form of an
exponential function. An example of the exponential function is shown in the
attached diagram.
Mathematically
exponential function can be expressed by the following equation.
<span>F(a) =
e^a, where a>0.</span>
The price of each caramel macchiato is $5.60
What is the correct function in this case?
The appropriate function is the one that considers the initial amount of $35 , the amount spent for 5 caramel macchiatos, and the balance left which is $7 after the purchase
This means the $35 minus the amount spent equals $7
let us assume that the price per item is x for 5 items, then he spent 5x
35-5x=7
35-7=5x
28=5x
x=28/5
x=$5.60
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a. The reason why this question is a binomial experiment is based on the fact that it is made up of an independent sample, it has a number that is fixed and a probability.
Each event is made up of two outcomes and they are random with the same success rate.
<h3>b. How to solve probability that exactly 5 had a bachelor</h3>
we have the following data n = 12, p = 0.27 and k = 5
We have to use the function to solve electronically
binompdf(n,p,k)
input the values
= binompdf(12,0.27,5)
This gives us
= 0.1255
<h3>(C) Probability that fewer than 5 have bachelor</h3>
We use the formula below
= binompdf(12,0.27,5-1)
This is = 0.7984
D. Probability of at least 5
1 - probability of fewer than 5
= 1 - 0.7984
= 0.2016
How to solve for the Mean = n*p
n = 12 , p = 0.27
Mean = 12*0.27 = 3.24
and
standard deviation = √npq
n = 12, p = 0.27 , q = 1- 0.27
= 0.73
sd = √12*.27*.73
= 1.54
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